F(x)=10x^2-50x-60

Solution for F(x)=10x^2-50x-60 equation:

(F)=10F^2-50F-60

We move all terms to the left:

(F)-(10F^2-50F-60)=0

We get rid of parentheses

-10F^2+F+50F+60=0

We add all the numbers together, and all the variables

-10F^2+51F+60=0

a = -10; b = 51; c = +60;
Δ = b2-4ac
Δ = 512-4·(-10)·60
Δ = 5001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-\sqrt{5001}}{2*-10}=\frac{-51-\sqrt{5001}}{-20}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+\sqrt{5001}}{2*-10}=\frac{-51+\sqrt{5001}}{-20}
$